- #1

- 6

- 0

integratio 1/x2+a2.dx=1

intervel0 to +infinity

find value of 'a'

intervel0 to +infinity

find value of 'a'

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter king imran
- Start date

- #1

- 6

- 0

integratio 1/x2+a2.dx=1

intervel0 to +infinity

find value of 'a'

intervel0 to +infinity

find value of 'a'

- #2

- 6

- 0

Help Me Inthis Question

- #3

Hootenanny

Staff Emeritus

Science Advisor

Gold Member

- 9,621

- 7

I'm guessing that your integrand, is something along the lines of;

[tex]\int^{\infty}_{0} \frac{1}{x^2} + a^2 \;dx = 1[/tex]

Please note, that the rules of this forum prohibit us to provide help to someone who has not attempted there homework question before hand (assuming of course this is homework). Perhaps, if you posted your attempt, we could help you further...

- #4

- 10

- 0

Just clearing up the interpretation. Since the original poster has access to the original problem anyway, this doesn't constitute helping him. ;)

--Stuart Anderson

- #5

Gib Z

Homework Helper

- 3,346

- 6

Maybe some trig will help you out?

- #6

Hootenanny

Staff Emeritus

Science Advisor

Gold Member

- 9,621

- 7

You are quite correct of course!

Just clearing up the interpretation. Since the original poster has access to the original problem anyway, this doesn't constitute helping him. ;)

--Stuart Anderson

And so it shouldThe Integral [tex]\int \frac{1}{x^2 + a^2} dx[/tex] looks very familiar to me :)

Good suggestionMaybe some trig will help you out?

- #7

- 6

- 0

find volume of solid y=x2-1 ,x=2 ,y=0 is relvived about y-asis

- #8

HallsofIvy

Science Advisor

Homework Helper

- 41,847

- 966

Also, since it is obviously homework, post it in the homework thread and show what you have tried!

- #9

- 3

- 0

plz give me good sites to refer for integration,its applications

- #10

- 5

- 0

\int {\frac{1}

{{x^2 + a^2 }}dx} = \frac{1}

{a}\tan ^{ - 1} \frac{x}

{a} + c

\][/tex]

Just in case.

- #11

- 410

- 12

does the following integral even exist?Hootenanny said:[tex]\int^{\infty}_{0} \frac{1}{x^2} + a^2 \;dx = 1[/tex]

[tex]\int^{\infty}_{0}\left(\frac{1}{x^2} + a^2\right) dx[/tex]

- #12

cristo

Staff Emeritus

Science Advisor

- 8,122

- 74

does the following integral even exist?

[tex]\int^{\infty}_{0}\left(\frac{1}{x^2} + a^2\right) dx[/tex]

Look at the above post:

Just clearing up the interpretation. Since the original poster has access to the original problem anyway, this doesn't constitute helping him. ;)

--Stuart Anderson

- #13

Gib Z

Homework Helper

- 3,346

- 6

does the following integral even exist?

[tex]\int^{\infty}_{0}\left(\frac{1}{x^2} + a^2\right) dx[/tex]

The question was actually with the a^2 also in the denominator, look at above posts. And that integral you stated only exists if a=0.

Share: